1.

Hydrogen atoms is a particular excited state 'n', when all returned to ground state, 6 different photons are emitted.Which of the followingis/are incorrect .

Answer»

out of 6 different PHOTONS only2 photons have speed equal to that of visible light
If highest energy photon emitted from the above sample is incident on the metal plate having work function 8 eV, KE of liberated photo-electron may be equal to or less than 4.75 eV
Total number of radial nodes in all the orbitals of `n^(th)` shell is 14
Total number of angular nodes in all the orbitals in `(n-1)^(th)` shell is 13

Solution :number of photons emitted=6
So, `(n(n-1))/2=6, n=4`
excited state is `3^(rd)` or n=4
photon having highest energy will ge `4to1`
So, its energy will be `=13.6(1/1^2-1/4^2)=13.6xx15/16=12.75`
when it is incident on plate having work function 8 eV then
KE=12.75-8=4.75
KE will be equal to this VALUE or may be less if electron is inner electron.So OPTION (B) is correct.Option (A) is incorrect because all photon have equal velocitywhich is `3xx10^8m//s`
( C),(D) also incorrect because number of nodes in `n^(th)` & `(n-1)^(th)` shall are 6(Radial node) & 3 (Angular node) RESPECTIVELY.


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