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Hydrogen gas is prepared in the laboratory by reacting dilute HCl with granulated zinc. Following reaction taken place : Zn+2HCl rarr ZnCl_(2)+H_(2) Calculate the volume of hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl.1 mol of a gas occupies 22.7 L volume at STP , atomic mass of Zn = 65.3 u. |
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Answer» Solution :1 MOLE of Zn, i.e., 65.3 g produced 1 mole of `H_(2)`, i.e., 22.7 L or STP `therefore"32.65 g of Zn will PRODUCE "H_(2)" at sTP"=(22.7)/(65.3)xx32.65=11.35L` |
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