1.

Hydrogenaton of vegetable thee at 25^(@)C reduces pressure of H_(2) from 2 atm to 1.2 atm in 50 minute. The rate of reaction in terms of molarity per second is

Answer»

`1.06xx10^(-6)`
`1.06xx10^(-5)`
`1.06xx10^(-7)`
`1.06xx10^(-9)`

Solution :`r_(((ATM)/t))=r_((M/t))xxRxxT,(r_(mu))/("sec")=0.00325/323=1.006xx10^(-5)`


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