1.

Hydrolysis of DDT is a first order reaction , its half life is 10 years . Time to hydrolyse 10 g DDT to half is

Answer»

100 YEARS
50 years
5 years
10 years

Solution :`K = (0.693)/(t_(1//2)) = (0.693)/(10 "years")`
If INITIAL concentration a = 10 gm and final concentration
`x = (a)/(2) = 5` gm
then , t = `(2.303)/(k)` log `(a)/(a-x) = (2.303)/(0.693) xx 10 xx "log" (10)/(5)`
`= (2.303 xx 10 xx "log" 2)/(0.693) = (2.303 xx 10 xx 0.301)/(0.693) = 10 ` years .


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