Hydrolysis of methyl acetate in aqueous solution has been studied by titrating the liberated acetic acid against sodium hydroxide. The concentration of an ester at different temperatures is given below. {:("t (min)",0,20,40,60,prop),("v (mL)",20.2,25.6,29.5,32.8,50.4):} Show that the reaction is the first order reactions.

Hydrolysis of methyl acetate in aqueous solution has been studied by t

1.	Hydrolysis of methyl acetate in aqueous solution has been studied by titrating the liberated acetic acid against sodium hydroxide. The concentration of an ester at different temperatures is given below. {:("t (min)",0,20,40,60,prop),("v (mL)",20.2,25.6,29.5,32.8,50.4):} Show that the reaction is the first order reactions.
Answer» Solution :`k=(2.303)/(t)"log"((V_(OO)-V_(0)))/((V_(oo)-V_(0)))` `V_(oo)-V_(0)=50.4-20.2=30.2` When t = 20 MTS. `k=(2.303)/(20)"log"(50.4-20.2)/(50.4-25.6)` `=0.1151"log"^(30.2)/(24.8)` `= 0.1151 log 1.2479` `= 0.1151xx0.0959` ` = 11.03xx10^(-3)"MIN"^(-1)` When t = 40 mts `k=(2.303)/(40)"log"(50.4-20.2)/(50.4-29.5)` `=0.0576xx "log"(30.2)/(20.9)` `= 0.0576xx0.1596` `= 9.19xx10^(-3)"min"^(-1)` When t = 60 mts `k=(2.303)/(60)"log"(50.4-20.2)/(50.4-32.8)` `= 0.03838xx "log"(30.2)/(17.6)` `=0.03838xx0.2343` `= 8.99xx10^(-3)"min"^(-1)` The constant values of k show that the REACTION is of first order.