1.

I_(2)(s) | I^(-) (0.1M) half cell is connected to a H^(+)(aq)| H_2("1 bar ") | Pthalf cell and e.m.f is found to be 0.7714 V . IfE_(I_2|I^(-))^(@) = 0.535 V, find the pH of H^(+) | H_2 half - cell .

Answer»


Solution :`Pt, (1)/(2) H_2 // H^(OPLUS) // I_((0.1))^(Ɵ) //(1)/(2) I_2 , Pt , (1)/(2) H_2 + (1)/(2) I_2 to H^(oplus) +I^(Ɵ)`
` E=E^(@) - (0.0591)/(n) log Q ,0.7714 = (0.535 -0) - (0.0591)/(1) log(H^(oplus))(I^(-))`
`-((0.07714 - 0.535)/(0.0591))log(H^(oplus)) (0.1) , log(H^(oplus))(0.1)=-((0.2364)/(0.0591))=(4)`
` (H^(oplus))(0.1) = 10^(-4) , (H^(oplus)) = (10^(-4))/(0.1) = 10^(-3) , P^(H) =3 `


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