1.

I amount of current is passed through a coil with N turns. Magnetic flux linked with the coil is ......

Answer»

LI
NLI
`(NI)/L`
`N^2LI`

SOLUTION :Self induction of coil is `L=Phi/I`
where `Phi` = total MAGNETIC flux linked with ENTIRE coil
I=current PASSING through the coil .
`therefore Phi=LI`


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