

InterviewSolution
Saved Bookmarks
1. |
(i) Calculate the first three energy levels for positronium. (ii) Fine the wavelength of the `H_(a)` line `(3 rarr2"transition")` of positronium. |
Answer» In positromium electron and positron revolve around their centre of mass `(1)/(4 pepsilon_(0))(e^(2))/(r^(2))=(mv^(2))/(r//2)`.......(1) `(nh)/(2pi)=2xxmv_(k//2)` From (1) & (2) `V=(1)/(2).(1)/(4 piepsilon_(0)).(e^(2))/(nh)xx2p=(e^(2))/(4 epsilon_(0)nh)` `TE= -(1)/(2) mv^(2)xx2= -m (e^(4))/(16 epsilon_(0)^(2)n^(2)h^(2))` `= -6.8(1)/(n^(2))eV` (i) `E_(1)= -6.8 ev` `E_(2)= -6.8xx(1)/(2^(2))eV= -1.70 eV` `E_(3)= -6.8xx(1)/(3^(2))eV= -0.76-(-1.70)eV` The corresponding wave length `lambda(1.24xx10^(4))/(0.94)Å=1313Å` (i) `-6.8eV, -1.7 eV, -0.76 eV`, (ii) `1313Å` |
|