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(i) Complete the following a. MnO_(4)^(2-)+H^(+) to ? b. C_(6)H_(5)CH_(3) underset(KMnO_(4))overset("acidified") to ? c. MnO_(4)^(-) +Fe^(2+) to ? (ii) What is linkage isomerism? Explain with an example. |
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Answer» Solution :(i) a. `underset("ion") underset("Manganate")(3MnO_(4)^(2-))+underset("MEDIUM")underset("Acid")(4H^(+))to underset("ion")underset("Permaganate")(2MnO_(4)^(-))+underset("DIOXIDE")underset("Manganese")(MnO_(2))+2H_(2)O` b. `underset("Toluene")(C_(6)H_(5)CH_(3))underset({:(KMnO_(4)),("Oxidation"):})overset("acidified")tounderset("Benzoic acid")(C_(6)H_(5)COOH)` c. `underset("ion")underset("Permanganate")(2MnO_(4)^(-))+underset("ion")underset("FERROUS")(10Fe^(2+))+16H^(+)underset(("Oxidation"))(to)2Mn^(2+)+underset("Ferric")(10Fe^(3+))+8H_(2)O` (ii) This type of isomers arises when an ambidentate ligand is bonded to the central metal atom/ion through either of its TWO different donor atoms. For examples, `[CO(NH_(3))_(5)ONO]Cl_(2)` (Pentaammine nitrito cobalt (III) chloride) O - attached. (Red in colour). `[Co(NH_(3))_(5)NO_(2)]Cl_(2)` (Pentaammine nitro cobalt (III) chloride) N - attached (Yellow-brown in colour). |
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