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(i) Complete the following equations : (a) 2MnO_(4)^(-)+ 5SO_(3)^(2-)+6H^(+)to (b) Cr_2O_(7)^(2-)+6Fe^(2+)+14H^(+)to (ii) Based on the data, arrange Fe^(2+), Mn^(2+) and Cr^(2+) in the increasing order of stability of +2 oxdiation state . E^(@) Cr^(3+)//Cr^(2+)=-0.4V E^(@) Mn^(3+)//Mn^(2+)=01.5V E^(@) Fe^(3+)//Fe^(2+)=+08V |
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Answer» Solution :(i)(a) `2MnO_4^(-)+5SO_(3)^(2-)+6H^(+)to 2Mn^(2+)+3H_2O+5SO_(4)^(2-)` (B) `Cr_2O_7^(2-)to 6Fe^(2+)+14H^(+)to 2Cr^(3+)+6Fe^(3+)+7H_2O` (ii) `E^(@) Cr^(3+)//Cr^(2+)=-0.4V` `E^(@) Mn^(3+)//Mn^(2+)=01.5V` `E^(@) Fe^(3+)//Fe^(2+)=+08V` INCREASING order of stability of `+2` oxidation state is : |
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