1.

(i) `cos3x=cos2x` (ii) `cos5x=sin3x` (iii) `cosmx=sinnx`

Answer» Correct Answer - (i) `x=2npiorx=(2npi)/(5)"where"n in I`
(ii) `x=((npi)/(4)+(pi)/(16))orx=(npi-(pi)/(4)),"where"n in I`
(iii) `x=((4k+1)pi)/(2(m+n))orx=((4k-1)pi)/(2(m-n)),"where"k inI`


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