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(i) `DeltaW_(AB)=5P_0V_0` (ii) `DeltaW_(BC)=0` (iii) `DeltaW_(CA)=-2P_0V_0` (iv) `DeltaW_(ABCA)=3P_0V_0`A. (i),(iii)B. (ii),(iii)C. (iii),(iv)D. all |
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Answer» Correct Answer - D `DeltaW_(AB)=(1)/(2)(P_0+4P_0)(3V_0-V_0)=5P_0V_0` `DeltaW_(BC)=0` `DeltaW_(CA)=-P_0(3V_0-V_0)=-2P_0V_0` `DeltaW_(ABCA)=DeltaW_(AB)+DeltaW(BC)+DeltaW_(CA)=3P_0V_0` |
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