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(i) [Fe(CN)_(6)]^(4-) and [Fe(H_(2)O)_(6)]^(2+)are of differet colours in dilute solution. Why?(ii) A complex is prepared by mixig CoCl_(3) and NH_(3) in the molar ratio of 1: 2.0.1 M solution of this complex was foind to be freeze at -0.372^(@) C. What is the formula of the complex ? K_(f)= 1.86^(@)C/M |
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Answer» Solution :(i) In both the cases Fe is in +2 state, it has 4 UNPAIRED electrons but `CN^(-)` and `H_(2)O` has different crystal field splitting energy. (ii) `DeltaT_(f)=i.K_(f)m`i= 2 means complex dissociate into TWO ions. Hence the formula is `[Co(NH_(3))_4(Cl_2)]Cl` |
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