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I for an A.P..,t6 =-10 and t14= 34. find the valueof t10. |
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Answer» t10=5*16/21=80/21Step-by-step EXPLANATION:t6=6/2 (2a+5d)=-102a+5d=-10/3.....................(1)t14==14/2(2a+13d)=342a+13d=34/7....................(2)ADDING(1) and (2)4a+18d=-10/3+34/7=1/21(-70+102)4a+18d=32/21or 2a+9d=16/21thus t10=5{ 2a+9d)t10=5*16/21=80/21 |
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