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i. `H_(2)(g) +CI_(2)(g)rarr 2HCI(g),DeltaH =- x kJ` ii. `NaCI +H_(2)SO_(4) rarr NaHSO_(4) +HCI, DeltaH =- y kJ` iii. `2H_(2)O +2CI_(2) rarr 4HCI +O_(2),DeltaH =- z kJ` From the above equations, the value of `DeltaH` of `HCI` isA. `-x kJ`B. `-y kJ`C. `-z kJ`D. `-x//2 kJ` |
Answer» Correct Answer - D As per definition, the equation `(i)` represents the formation of `2` moles of `HCl`. Hence `DeltaH_(f)` of `HCl(g)=-X//2kJ mol^(-1)`. |
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