I have a total of Rs 300 in coins of denomination Re 1, Rs 2 and Rs 5.

1.	I have a total of Rs 300 in coins of denomination Re 1, Rs 2 and Rs 5. The number of Rs 2 coins is 3 times the pumber of Rs 5 coins. The total number of coins is 160. How many coins of cach denomination are with me?
Answer» Answer: so the number of coin of 5 = 20 COINS so the number of coin of 2 = 60 coins so the number of coin of 1 = 80 coins Step-by-step explanation: Let the number of coin 5 = Rs.x so the number of coin 2 = 3x so the number of coin 1 = 160 - 4x so AMOUNT of rs.5 = 5x so the amount of rs.2 = 6X a/q 5x + 6x + 160 - 4x = 300 7x = 300 - 160 7x = 140 x = 20 so the number of coin of 5 = 20 coins so the number of coin of 2 = 60 coins so the number of coin of 1 = 80 coins

I have a total of Rs 300 in coins of denomination Re 1, Rs 2 and Rs 5. The number of Rs 2 coins is 3 times the pumber of Rs 5 coins. The total number of coins is 160. How many coins of cach denomination are with me?

Answer»

Answer:

so the number of coin of 5 = 20 COINS

so the number of coin of 2 = 60 coins

so the number of coin of 1 = 80 coins

Step-by-step explanation:

Let the number of coin 5 = Rs.x

so the number of coin 2 = 3x

so the number of coin 1 = 160 - 4x

so AMOUNT of rs.5 = 5x

so the amount of rs.2 = 6X

a/q

5x + 6x + 160 - 4x = 300

7x = 300 - 160

7x = 140

x = 20

so the number of coin of 5 = 20 coins

so the number of coin of 2 = 60 coins

so the number of coin of 1 = 80 coins