.(i) How many electrons can be filled in all the orbitals with n+l 5(i

1.	.(i) How many electrons can be filled in all the orbitals with n+l 5(ii) Write the electronicconfiguration of Ni2 ion. How many unpaired electrons are present?(atomic number of Ni-28)
Answer» n can take values like 1,2,3.. l can take values from 0 to (n-1) This means l can’t be greater than n. Now lets look at all the possible combinations to get n+l=5 They would be- n=3 l=2 n=4 l=1 n=5 l=0 Now lets look at all cases one by one - n=3 , l=2 it would mean 3d orbital which can accomodate maximum10 electrons. Similarly , n=4 , l=1 Max. electrons=6 n=5 , l=0 Max. electrons=2 Total adds up to18.

.(i) How many electrons can be filled in all the orbitals with n+l 5(ii) Write the electronicconfiguration of Ni2 ion. How many unpaired electrons are present?(atomic number of Ni-28)

Answer»

n can take values like 1,2,3..

l can take values from 0 to (n-1)

This means l can’t be greater than n.

Now lets look at all the possible combinations to get n+l=5

They would be-

n=3 l=2

n=4 l=1

n=5 l=0

Now lets look at all cases one by one -

n=3 , l=2

it would mean 3d orbital which can accomodate maximum10 electrons.

Similarly ,

n=4 , l=1

Max. electrons=6

n=5 , l=0

Max. electrons=2

Total adds up to18.