(i) In ∆ABC, if a = 2, b = 3 and sin A=2/3then∆B= (A)π\4(B)π\2(C

1.	(i) In ∆ABC, if a = 2, b = 3 and sin A=2/3then∆B= (A)π\4(B)π\2(C)π\3(D)π\6
Answer» Answer: (C) π\3 is the CORRECT answer Step-by-step EXPLANATION: SIN A =2/3 which means C/B, so C=2 and B =3 and on reciprocal becomes π/3. Hope it helps. Mark me as Brainliest. Much love. Thank you.

(i) In ∆ABC, if a = 2, b = 3 and sin A=2/3then∆B= (A)π\4(B)π\2(C)π\3(D)π\6

Answer»

Answer:

Step-by-step EXPLANATION:

SIN A =2/3 which means C/B,

so C=2 and B =3 and on reciprocal becomes π/3.

Hope it helps.

Mark me as Brainliest.

Much love.

Thank you.

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(i) In ∆ABC, if a = 2, b = 3 and sin A=2/3then∆B= (A)π\4(B)π\2(C)π\3(D)π\6 ​

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(i) In ∆ABC, if a = 2, b = 3 and sin A=2/3then∆B= (A)π\4(B)π\2(C)π\3(D)π\6