(i) Ionic conductance at infinite dilution of Al^(3+)and SO_4^(2-) are 189 and 160 mho cm^2 "equity "^(-1). Calculate the equivalent and molar conductance of the electrolyte Al_2(SO_4)_3 at infinite dilution . (ii) Suggest a way to determine lamda_m^@ value of water . (b) (i) Why does bleeding stop by rubbing moist alum. (ii) How is glycerol reacts with fuming nitric acid ? (or) How would you convert glycerol into nitroglycerine ?

(i) Ionic conductance at infinite dilution of Al^(3+)and SO_4^(2-) are

1.	(i) Ionic conductance at infinite dilution of Al^(3+)and SO_4^(2-) are 189 and 160 mho cm^2 "equity "^(-1). Calculate the equivalent and molar conductance of the electrolyte Al_2(SO_4)_3 at infinite dilution . (ii) Suggest a way to determine lamda_m^@ value of water . (b) (i) Why does bleeding stop by rubbing moist alum. (ii) How is glycerol reacts with fuming nitric acid ? (or) How would you convert glycerol into nitroglycerine ?
Answer» Solution :(i) Molar conductance `(^^^_m^@)_(Al_2(SO_4)_3)=2(lamda_m^@)_(Al^(3+))+3(lamda_m^@)_(SO_4^(2-))` `=(2xx189)+(3xx160)=378+480=858 mho " cm"^2"mol"^(-1)` 2. Equivalent conductance `(lamda_(oo))_(Al_2(SO_4)_3)=1/3(lamda_oo)_(Al^(3+))+1/2(lamda_oo)_(SO_4^(2-))` `=189/3+160/2 = 63+80=143 "mho cm"^2 ("G equiv")^(-1)` (ii) `lamda_m^@(H_2O)=lamda_(H^+)^@+lamda_(OH)^@-` We FIND out `lamda_m^@(HCL), lamda_m^@(NAOH)and lamda_m^@(NaCl)` Then `lamda_m^@(H_2O), lamda_m^@(HCl)+ lamda_m^@(NaOH)lamda_m^@(NaCl)`