-STEP explanation:Given :Dimensions of the cuboidal solid block = 30 CM × 40 cm × 50cm.andForce applied by block = 50 NWe have to find :The MAXIMUM pressure that will be exerted by the block on ground.Solution :Dimensions of the cuboidal solid block= 30 cm × 40 cm × 50cm.= 0.3 m × 0.4 m × 0.5 m. [ in meter ]Now,Area of the first face =A_1A 1 = 0.3 × 0.4 = 0.12 m²֎ Area of the second face =A_2A 2 = 0.4 × 0.5 = 0.20 m²֎ Area of the third face =A_3A 3 = 0.5 × 0.3 = 0.15 m²Here we can see that, out of the above three faces , A_1A 1 is minimum.Here, we consider the minimum value of area to calculate the maximum pressure becausewe know that,\begin{gathered}P ∝ \frac{1}{A} < /p > < p > \\ \END{gathered} P∝ A1

The relation between Pressure (P) , Force(F) and Area (A) is given by ,\begin{gathered}\: {\large{{ \bf{Pressure= \dfrac{Force}{Area}}}}}\\ \implies \sf \: P = \dfrac{F}{A_1}\\ \implies \sf \: P = \dfrac{50 \: N}{0.12 \: {m}^{2} } \\ \\ \implies \red{\boxed{ \green{ \bf{P = 416.66 \: N{m}^{ - 2} }} }}\: \end{gathered} Pressure= AreaForce ⟹P= A 1 F ⟹P= 0.12m 2 50N ⟹ P=416.66Nm −2 ∴ The maximum pressure applied by the given cuboidal solid block is 416.6 N/m².