I mark u brainlist if sinA=1/p then find cosA×cosecA+tanA×sec A

1.	I mark u brainlist if sinA=1/p then find cosA×cosecA+tanA×sec A
Answer» <P>Step-by-step EXPLANATION: sinA=1/p cosecA= p cosA=√(1-sin²A)=√(1-1/p²)={√(p²-1)}/p secA=p/{√(p²-1)} tanA=sinA/cosA=1/√(p²-1) PUT these values in yr eq cosA×cosecA+tanA×sec A=√(p²-1)+p/(p²-1) =[(p²-1){√(p²-1)}+p]/(p²-1) answer

Answer»

<P>Step-by-step EXPLANATION:

sinA=1/p

cosecA= p

cosA=√(1-sin²A)=√(1-1/p²)={√(p²-1)}/p

secA=p/{√(p²-1)}

tanA=sinA/cosA=1/√(p²-1)

PUT these values in yr eq

cosA×cosecA+tanA×sec A=√(p²-1)+p/(p²-1)

=[(p²-1){√(p²-1)}+p]/(p²-1)

answer

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I mark u brainlist if sinA=1/p then find cosA×cosecA+tanA×sec A​

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I mark u brainlist if sinA=1/p then find cosA×cosecA+tanA×sec A