1.

(i) P+C("carbon")+Cl_(2) to Q+CO uaarr (ii) Q+H_(2)O to R+HCl (iii) BN+H_(2)O to R+NH_(3) uarr (iv) Q+LiAlH_(4) to S+LiCl+AlCl_(3) (v) S+H_(2) to R+H_(2) uarr (vi) S+NaH to T (P,Q,R,S annd T do not represent their chemical symbols) Q. Compound S is: (I) an odd e^(-) compound (II) (2c-3e^(-)) compound (III) a electron deficient compound (IV) a sp^(2) hybridized compound Choose the correct code:

Answer»

III
I,III
II,III,IV
I,II,IV

Solution :(i)`B_(2)O_(3)+UNDERSET((P))(3C)+3Cl_(2)to2BCl_(3)+underset((Q))(3CO)uarr`
`(ii) underset((Q))(BCL_(3))+3H_(2)OtoH_(3)BO_(3)+3HCL`
(iii) `BN+3H_(2)Otounderset((R))(H_(3)BO_(3))+NH_(3)`
(iv) `underset ((Q))(4BCl_(3))+3LiAlH_(4)tounderset((S))(2B_(2)H_(6))+3LiCl+3AlCl_(3)`
(v) `underset((S))(B_(2)H_(6))+6H_(2)Otounderset((R))(2H_(3)BO_(3))+6H_(2)uarr`
(vi) `underset((S))(B_(2)H_(6))+2NaHtounderset((T))(2NaBH_(4))`


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