1.

(i)P+C("carbon")+Cl_(2)toQ+CO uarr , (ii)Q+H_(2)OtoR+HCl (iii)BN+H_(2)O to R+NH_(3) , (iv)Q+LiAIH_(4) to S+LiCl+ AlCl_(3) (v)S+H_(2)toR+H_(2) uarr , (vi)S+NaH to T (P,Q,R,S and T do not represent their chemical symbols) Compound Q has: (I) zero dipole moment (II) a planer trigonal structure (III) an electron deficient compound (IV) a Lewis base Choose the correct code.

Answer»

I,IV
I,II,IV
I,II,III
I,II,III,IV

Solution :(i)`B_(2)O_(3)(P)+3C+3Cl_(2) to 2BCl_(3) (Q) +3CO uarr`
(ii)`BCl_(3)(Q)+3H_(2)O to H_(3)BO_(3)(R)+3HCl`
(iii)`BN+3H_(2)O to H_(3)BO_(3)(R) + NH_(3)`
(iv)`4BCl_(3)(Q)+3LiAlH_(4) to 2B_(2)H_(6)(S)+3LiCl+3AlCl_(3)`
(v)`B_(2)H_(6)+6H_(2)O to 2H_(3)BO_(3) (R)+6H_(2) uarr`
(vi)`B_(2)H_(6)(S)+2NaH to 2NaBH_(4)(T)`


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