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I st question is 3xy×(4x²+y) and second is-3p²q²(4P²q-3pq²+4P -5 q) |
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Answer» =(x-y)(4x+y+2) Step-by-step explanation: 4x2−y2−3xy+2x−2y=(4x2−(4y2−3y2)−3xy+2x−2y) =(4x2−4y2)+(3y2−3xy)+(2x−2y)=4(x2−y2)+3Y(y−x)+2(x−y) =4(x+y)(x−y)−3y(x−y)+2(x−y)=(x−y)(4(x+y)−3y+2)=(x−y)(4x+4y−3y+2) =(x−y)(4x+y+2) |
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