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I toss three coins together. The possible outocmes are no heads, 1 head 2 head and 3 heads. So, I say that prbability of no heads is `(1)/(4)`. What is wrong with this conclusion?

Answer» I toss three coins together
So, total number of outcome `=2^(3)=8`
and possible outcomes are (HHH),(HTT),(THT),(TTH),(HHT),(THH),(HTH),and (TTT)
Now, probability of getting no head=`(1)/(8)`
Hence, the given conclusion is wrong because the probability of no head is `(1)/(8) not (1)/(4)`


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