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Refer to 0.28. What is the probablity that the card is (i) a club (ii) 10 of hearts |
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Answer» (i) Let `E_(3)`=Event of getting a club `n(E_(3))`=(13-3)=10 `therefore "Required probability"=(n(E_(3)))/(n(S))=(10)/(49)` (ii) Let `E_(4)`=Event of getting 10 g of hearts `n(E_(4)=1` [Because in 52 playing cards only 13 are the heart cards and only one 10 in 13 heart cards] `therefore "Required probability"=(n(E_(4)))/(n(S))=(1)/(49)` |
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