(i) When 2.56 g of sulphur was dissolved in 100 g of CS_(2), the freez – InterviewSolution

1.	(i) When 2.56 g of sulphur was dissolved in 100 g of CS_(2), the freezing point lowered by 0.383 K . Calculate the formula of sulphur (S_(x))(K_(f)" for "CS_(2)="3.83 K kg mol"^(-1)), (Atomic mass of sulphur = "32 g mol"^(-1)).
Answer» Solution :(i) `S_(8)`, SIMILAR to SOLVED problem 6,

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