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(i) Which is a stronger reducing agent Cr^(2+) or Fe^(2+) and why ? (ii) Explain why Cu^(+) ion is not stable in aqueous solution ? (iii) Explain why Ce^(4+) is a stronger oxidizing agent. |
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Answer» Solution :(i) `Cr^(2+)` is a stronger reducing agent than `Fe^(2+)` because `Cr^(2+) rarr Cr^(3+) + e^(-)` results in CHANGE of configuration from `d^(4)` to more stable `d^(3) ( t_(2g)^(3))` than from `d^(6)` to `d^(5)` in case of the change `Fe^(2+) rarr Fe^(3+) + e^(-)` . (ii) This is because `Cu^(+)` ion in aqueous solution undergoes disproportionation to give more stable `Cu^(2+)` and Cu. (iii) This is because`CE^(4+)` TENDS to change to `Ce^(3+)` as `+3` oxidation state is more stable. |
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