iam aheight op imос у g.tri kes uu 8round and lossesst. 4/AS-tri25. p abody te beunds to a height op

iam aheight op imос у g.tri kes uu 8round and lossesst. 4/AS-tri25.

1.	iam aheight op imос у g.tri kes uu 8round and lossesst. 4/AS-tri25. p abody te beunds to a height op
Answer» <p>answer is 12meters.</p><p>initially when the body is dropped, u=0, distance travelled is 16m therefore final velocity before hitting the ground is</p><p>v^2=u^2+ 2as</p><p>v^2= 2x gx 16.</p><p>since 25% kinetic energy is lost in collision, the energy left in the body is 75%</p><p>therefore 75/100 x 1/2mv^2= mgh</p><p>wherehis the distance to which it rebounds.</p><p>m on both sides gets cancelled, on putting the value of v^2in the above equation you geth= 12m</p>