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Ice at 0^(@)C enclosed in an adiabatic shell and is compressed to a pressure of 600 atm. It is known that an increase in the pressure of 138 atm causes the melting point of ice to drop by 1 K. Assuming the phase diagram in this part to be linear, find the fraction of the ice that is going to melt. |
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Answer» SOLUTION :First find the melting points `t=-Deltap//k=-4.35^(@)C`. As the ICE is cooled to this temperature, the heat liberated is `Q=mcDeltat= mc|t|` This heat will be SPENT to melt the ice `Q_(m)=m_(1) lambda`. Hence the fraction of the ice that will melt will be `x=(m_(1))/(m)=(c|t|)/(lambda)`. In the calculation assume that the specific heat of ice and the heat of melting remain CONSTANT. |
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