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Ice with mass `m_(1)=600g` and at temperature `t_(1)=-10^(@)C` is placed into a copper vessel heated to `t_(2)=350^(@)C`. As a result, the vessel now contains `m_(2)=550g` of ice mixed with water. Find the mass of the vessel. The specific heat of copper `=0.1"cal"//C^(@)g` and sp. heat of ice `=0.5"cal"//gC^(@)`. Latent heat of ice `=80"cal"//g`.

Answer» Correct Answer - `200g`


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