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Identify A to E |
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Answer» Solution :Gas (B) gives brownppt with `K_(2)HgI_(4)` `rArr` gas (B) is `NH_(3)` `rArr (A)` is `NH_(4)^(Theta)` Gas (C ) turn water MILKY `rArr (C )` can be `SO_(2)` or `CO_(2)` Gas (D) is also obtain along with (C ) , gas (D) turnwith blue flame and is fatal when inbaled `rArr` gas (D) is `CO` `rArr` gas (C ) is `CO_(2)` `rArr (A)` has `C_(2)O_(4)^(2+)` It is condiremed by the fact that `CaCI_(3)` gives ppt `CaC_(3)O_(4)(E )` which decolourises `MnO_(4)^(Theta) H^(Theta)` `rArr (A)` is `(NH_(6))_(2)C_(2)O_(4)` Explanation: `underset((A))((NH_(4))_(2))C_(2)O_(4) overset(Delta)rarr underset((B))(2NH_(3)) + underset((C))(CO_(2)) + underset((D))(CO)+H_(2)O` (B) is blue towards litmus (basic) (C) is red towards litmus (acidic) (D) is neutral `(NH_(4))C_(2)O_(4) +2NaOH overset(Delta)rarr Na_(2)C_(2)O_(4) + underset((B))(2NH_(3)) + 2H_(2)O` `Na_(2)C_(2)O_(4) +CaCI_(2) rarr underset("white ppt") (CaC_(2)O_(4)darr) +2NaCI`  `underset("Violet")(2MnO_(4)^(Theta)) 16 H^(o+) +5C_(2)O_(4)^(2-) rarr 10 CO_(2) +underset("Colourless")(2Mn^(2+)) +H_(2)O` |
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