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Identify A to E and explain the reactions involved. |
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Answer» SOLUTION :The compounds A to E are `{:(A=CU,,B=Cu(NO_(3))_(2),,C=[Cu(NH_(3))_(4)]^(2+)),(D=CO_(2),,E=CaCO_(3),,F=Cu_(2)[Fe(CN)_(6)]),(G=Ca(HCO_(3))_(2),,,,):}` The reactions are explained as under : `CuCO_(3)toCuO+CO_(2)` `2CuO+CuS to underset((A))(3Cu)+SO_(2)` `Cu+4HNO_(3)overset("CONC.")to underset((B))(Cu(NO_(3))_(2)+2NO+2H_(2)O` `underset((B))(Cu^(2+))+NH_(3)to[Cu(NH_(3))_(4)]^(2+)` `Ca(OH)_(2)+underset((D))(CO_(2))to underset((E))CaCO(3)+H_(2)O` `CaCO_(3)+H_(2)O+CO_(2)to Ca(HCO_(3))_(2)` |
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