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Identify all the possible products in the given reaction. One or more options may be correct. CH_(3)-C -=CH + Me_(3)C - Br overset(NaNH_(2))to ? (1) Me_(3) - C - C -= C - Me(2) Me_(2)C = CH_(2) (3) Me_(3)C - CH_(2)- C -= CH(4) CH_(3)C -= CH |
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Answer» SOLUTION :`underset("Acidic Hydrogen")underset("Terminal alkyne")(CH_(3) - C -=overset(delta-)(CH^(delta+)))overset(NaNH_(2))to underset("Propynide anion")(CH_(3)- C -= bar(C) - Na^(+))` Propynide anion can act as nucleophile and also as a base. `Me_(3)-C-Br` (tert. butyl bromide) is a tertiary (`3^(@))` halide , which prefers elimination over SUBSTITUTION. `CH_(3)- underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-Br + underset("as base")(CH_(3) - C -= to underset ("Elimination Product" ("Major"))(CH_(3)-overset(CH_(3))overset(|)C = CH_(2)) + CH_(3) - C -= CH`  Hence the CORRECT options are (1), (2) and (4). |
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