1.

Identify B

Answer»

`ZnSO_(4)`
`CuSO_(4)`
`MgSO_(4)`
`FeSO_(4)`

Solution :(A) is `FeSO_(4).7H_(2)O`
`underset("Light green (A)")(FeSO_(4).7H_(2)O)overset("Gentle heating")tounderset("Colourless")(FeSO_(4))+7H_(2)O`
`FeSO_(4)+NO to underset("Brown (C)")(FeSO_(4).NO)`
`FeSO_(4)+NO to overset(Delta)underset((D))(Fe_(2)O_(3))+underset((E))(SO_(2))+underset((F))(SO_(3))`
`2KMnO_(4)+3H_(2)SO_(4)toK_(2)SO_(4)+2MnSO_(4)+3H_(2)O+5[O]`
`SO_(2)+H_(2)O+O to [H_(2)SO_(4)]XX5`
`ulbar(underset("(PINK)")(2KMnO_(4))+2H_(2)O+5SO_(2) underset("(Almost colourless)")(to) K_(2)SO_(4)+2MnSO_(4)+2H_(2)SO_(4)+2H_(2)SO_(4))`
`SO_(3)+H_(2)Oto H_(2)SO_(4)`
`H_(2)SO_(4)+BaCl_(2)toBaSO_(4)darr+2HCl`


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