1.

Identify disproportionation reaction :

Answer»

`CH_(4)+2O_(2)toCO_(2)+2H_(2)O`
`CH_(4)+4Cl_(2)toC Cl_(4)+4HCl`
`2F_(2)+2OH^(-)to2F^(-)+OF_(2)+H_(2)O`
`2NO_(2)+2OH^(-)toNO_(2)^(-)+NO_(3)^(-)+H_(2)O`

Solution :`2NO_(2)+2OH^(-)toNO_(2)^(-)+NO_(3)^(-)+H_(2)O` is a disproportion REACTION because N is both oxidised as WELL as reduced.O.N increases from `+4` (in `NO_(2))` to +3 (in `NO_(2)^(-))`.


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