Identify the chain initiation step of the polymerisation of ethene in the presence of benzoyl peroxide initiator, from the following?(a) C6H5• + C2H4 = C6H5-CH2-CH2•(b) C6H5-CH2-CH2• + C2H4 = C6H5-CH2-CH2-CH2-CH2•(c) C6H5-CH2-CH2-CH2-CH2• = C6H5-(-CH2-CH2-)n-CH2•(d) C6H5-(-CH2-CH2-)n-CH2• + C6H5-(-CH2-CH2-)n-CH2• = C6H5-(-CH2-CH2-)n-C6H5I got this question in an interview for internship.Enquiry is from Types of Polymerisation Reactions in division Polymers of Chemistry – Class 12

Identify the chain initiation step of the polymerisation of ethene in

1.	Identify the chain initiation step of the polymerisation of ethene in the presence of benzoyl peroxide initiator, from the following?(a) C6H5• + C2H4 = C6H5-CH2-CH2•(b) C6H5-CH2-CH2• + C2H4 = C6H5-CH2-CH2-CH2-CH2•(c) C6H5-CH2-CH2-CH2-CH2• = C6H5-(-CH2-CH2-)n-CH2•(d) C6H5-(-CH2-CH2-)n-CH2• + C6H5-(-CH2-CH2-)n-CH2• = C6H5-(-CH2-CH2-)n-C6H5I got this question in an interview for internship.Enquiry is from Types of Polymerisation Reactions in division Polymers of Chemistry – Class 12
Answer» Right ANSWER is (a) C6H5• + C2H4 = C6H5-CH2-CH2• To elaborate: BENZOYL peroxide undergoes homolytic fission to from phenyl free radical which ACTS an initiator. The first step is the ADDITION of this radical to the ethene double bond, thus GENERATING a new and larger free radical. This is called the chain initiating step.

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