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Identify the conjugate acid base pair for the following reaction in aqueous solution HS^-(aq)+HF leftrightarrow F^(-) (aq) +H_2S (aq) (ii) HPO_4^(2-)+ SO_3^(2-) leftrightarrow PO_4^(3-)+HSO_3^(-) (iii) NH_4^(+)+CO_3^(2-) leftrightarrow NH_3+HCO_3^(-) |
Answer» Solution : `HF and F^-,HS^- and H_2S` are TWO conjugate ACID-base PAIRS. `F^-` is the conjugate base of the acid HF (or) HF is the conjugate acid of `F^-` `H_2S` is the conjugate acid of `HS^-` (or) `HS^-` is the conjugate base of `H_2S`.  `HPO_4^(2-) and PO_4^(3-), SO_3^(2-) and HSO_3^(-)` are two conjugate acid-base pairs. `PO_4^(3-)` is the conjugate base of the acid `HPO_4^(2-)` (or)`HPO_4^(2-)` is the conjugate acid of `PO_4^(3-)` `HSO_3^(-)` is the conjugate acid of `SO_3^(2-)` (or) `SO_3^(2-)` is the conjugate base of `HSO_3^(-)`  `NH_4^(+) and NH_3,CO_3^(2-) and HCO_3^-` are two conjugate acid -base pairs. `HCO_3^-` is the conjugate of acid `CO_3^(2-)` (or) `CO_3^(2-)` is the conjugate bases of `HCO_3^-`. `NH_4` is the conjugate base of `NH_4^(+)` (or) `NH_4^(+)` is the conjugate acid of `NH_3` |
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