1.

Identify the correct statement(s)

Answer»

SERIES limit of paschen series in `Li^(2+)` ion is 13.6 eV
Wave number of last line of Balmer series in `He^(+)` ion is 'R' (R-Rydberg constant)
Maximum value of (n+l) in `._24Cr` is 5
Different types of orientation in space for 'f' orbital is 5

Solution :(A)Series limit of paschen series of `Li^(2+)=13.6xx3^2/3^2=13.6 eV`
(B)`(BARV)` of last line of Balmer series =`R/2^2xx2^2=R`
(C )In the comfiguration of `._24 Cr` there is '3d' HENCE maximum value of 'n+l' is 5
(D)Different types of orientation in space=(2l+1).So for 'f' orbitals l=3 and no of orientation =(2 X 3+ 1)=7


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