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Identify the expression for the magnetic field on the axis of circular loop.(a) B=\( \frac {\mu_o Ir}{4 \pi \big ( (r^2 \, + \, x^2)^{\frac {1}{2}} \big ] } \)× 2πr(b) B=\( \frac {\mu_o Ir}{4 \pi \big ( (r^2 \, + \, x^2)^{\frac {3}{2}} \big ] } \)(c) B=\( \frac {\mu_o Ir}{4 \pi \big ( (r^2 \, + \, x^2)^{\frac {3}{2}} \big ] } \)× 2πr(d) B=\(\frac {\mu_o Ir}{4 \pi \big ( (r^2 \, + \, x^2)^{\frac {1}{2}} \big ] } \)× 4πrI got this question during an interview.My enquiry is from Magnetic Field on the Axis of a Circular Current Loop in portion Moving Charges and Magnetism of Physics – Class 12

Answer»

Correct answer is (C) B=\( \frac {\mu_o IR}{4 \pi \big ( (r^2 \, + \, x^2)^{\frac {3}{2}} \big ] } \)× 2πr

Best explanation: The EXPRESSION for MAGNETIC field on the axis of circular loop is given as:

B=\( \frac {\mu_o Ir}{4 \pi \big ( (r^2 \, + \, x^2)^{\frac {3}{2}} \big ] } \)× 2πr

It is towards the loop if current in it is in clockwise direction and it is away from the loop if current in it is in anticlockwise direction.



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