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Identify the products A and B formed in the following reaction :CH_(3)-CH_(2)-CH=CH-CH_(3)+HCl to A+B |
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Answer» SOLUTION :The given alkene is unsymmetrical. Thus REACTION takes place as per Markovnikov.s RULE. `underset(darr)(CH_(3)CH_(2)CH-CH=CH-CH_(3)+HCl` `underset("2-Chloropentane")underset("(Major) (A)")(CH_(3)-CH_(2)-CH_(2)-underset("I")underset("|")("C")H-CH_(3))+underset("3-Chloropentane")underset("(Minor) (B)")(CH_(3)-CH_(2)-underset("I")underset("|")("C")H-CH_(2)-CH_(3))` |
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