Identify the relationship between base current amplification (α) and emitter current amplification (β).(a) β=\(\frac {\alpha }{1- \alpha}\)(b) β=\(\frac {1 – \alpha }{\alpha}\)(c) β=\(\frac {\alpha }{1 + \alpha}\)(d) β=\(\frac {1 + \alpha }{1 – \alpha}\)I had been asked this question in examination.The doubt is from Semiconductor Electronics in chapter Semiconductor Electronics : Materials, Devices and Simple Circuits of Physics – Class 12

Identify the relationship between base current amplification (α) and

1.	Identify the relationship between base current amplification (α) and emitter current amplification (β).(a) β=\(\frac {\alpha }{1- \alpha}\)(b) β=\(\frac {1 – \alpha }{\alpha}\)(c) β=\(\frac {\alpha }{1 + \alpha}\)(d) β=\(\frac {1 + \alpha }{1 – \alpha}\)I had been asked this question in examination.The doubt is from Semiconductor Electronics in chapter Semiconductor Electronics : Materials, Devices and Simple Circuits of Physics – Class 12
Answer» The CORRECT choice is (a) β=\(\FRAC {\ALPHA }{1- \alpha}\) To explain: IE=IB+IC \(\frac {I_E}{I_C} =\frac {I_B}{I_C}\) + 1 \(\frac {1}{\alpha }=\frac {1}{\BETA }\) + 1 α = \(\frac {\beta }{1 + \beta}\) Therefore, β=\(\frac {\alpha }{1- \alpha}\)

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