IE1 and IE2 of magnesium are 7.6 eV and 15.0 eV respectively. The amou – InterviewSolution

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1.	IE1 and IE2 of magnesium are 7.6 eV and 15.0 eV respectively. The amount of energy in kJ needed to convert all the atoms of magnesium into Mg2+ ions present in 36 mg of magnesium vapour will be:[Given: 1 eV=96.5 kJ mol–1].
Answer» $I E_{1}$ and $I E_{2}$ of magnesium are $7.6 eV$ and $15.0 eV$ respectively. The amount of energy in $kJ$ needed to convert all the atoms of magnesium into $M g^{2 +}$ ions present in $36 mg$ of magnesium vapour will be: [Given: $1 eV = 96.5 {kJ mol}^{- 1}$ ].

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