1.

If 0.2 mol of O_(2) vapours can effuse from an opening in a heated vessel in 20 second how long will it take 8 gm H_(2) (g) to effuse under same conditions.

Answer»

`600 sec`
`100 sec`
`400 sec`
`200 sec`

Solution :`(r_(O_(2)))/(r_(H_(2))) = SQRT((M_(H_(2)))/(M_(O_(2))))`
`((DELTA n)/(t))_(o_(2))/(((Delta n)/(t))_(H_(2))) = sqrt((2)/(32))`
`((0.2)/(20))/((4)/(t)) = sqrt((1)/(16))`
`t = (400)/(4) = 100 sec`


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