1.

If 0.228 g of silver salt of dibasic acid gabe a residue of 0.162 g of silver on ignition then molecular weight of the acid is

Answer»

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Solution :Mass of silver SALT taken `=0.228 gm`
Mass of silver LEFT `= 0.162gm`
Basicity of ACID `= 2`
Step 1 : To calculate the EQUIVALENT mass of the silver salt (E ).
`(" Eq.mass of silver salt")/(" Eq. mass of silver ") = (" Mass of acid taken ")/(" Mass of silver left ")`
`= E/ 108 = (0.0228)/(0.162)`
`= E = (0.228)/(0.162) xx 108 = 152` (Eq. mass of silver salt)
Step 2. to calculate the eq. mass of acid .
Eq. mass of acid = Eq. mass of silver salt - Eq. mass of Ag + Basicity
`= 152- 108 +1 = 152 - 107 = 45` (Eq. mass of acid)
Step 3 : To determine the molecular mass of acid.
Mol. mass of the acid = Eq. mass of acid `xx` basicity
`= 45 xx 2 = 90`.


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