1.

If 0.2g of a gas 'X' occupies a volume of 440 ml and if 0.1 g of CO_(2) gas occupies a volume of 320 ml at the same temperature and pressure , X could be

Answer»

`O_(2)`
NO
`C_(4) H_(10)`
`SO_(2)`

Solution :At same T and p,
`( V_(1))/( V_(2))= ( n_(1))/(n_(2)) = ( W_(1)//M_(1))/(W_(2)//M_(2))`
`( 440 ML )/( 320ml ) = ( 0.2 //M_(1))/( 0.1 // 44 )`
`:. M _(1) = 66g mol^(-1)`
Hence gas X could be `SO_(2)`


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