If 0.5 amp current is passed through acidified silver nitrate solution – InterviewSolution

1.	If 0.5 amp current is passed through acidified silver nitrate solution for 100 minutes the mass of silver deposited on cathode, is (eq. wt. of silver nitrate=108) :
Answer» 2.3523 g 3.3575 g 5.3578 g 6.3575 g Solution :(b) Current (I) =0.5 amp. TIME (t)=100 MM `=100xx60 sec.=6000 s`. EQ. MASS of Ag (E ) =108 `W=(EIt)/(96500)=(108xx0.5xx6000)/(96500)=3.3575 g`.

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