1.

If 0.5 g of a solute (molar mass 100 g mol^(-1)) in 25 g of solvent elevates the boiling point by 1 K, the molar boiling point constant of the solvent is

Answer»

2
8
5
`0.5`

Solution :`K_(B)=(DELTA T_(b)xx m_(B)xx w_(A))/(w_(B)xx1000)`
`K_(b)=(1xx100xx25)/(0.5xx1000)=5.00`


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