1.

If 0.561 g KOH is dissolved in water to give 200mL of solution at 298 K, calculate the concentration of potassium, hydrogen and hydroxyl ions. What is the pH ?

Answer»

SOLUTION :`[KOH]=0.561/56 times1000/200M=0.050M`
`As KOH toK^+ +OH^-,therefore[K^+][OH^-]=0.05M`
`[H^+]=K_w//[OH^-]=10^-14//0.05=10^-14//(5 times10^-2)=2.0 times10^-13M`
`pH=-LOG[H^+]=-log(2.0 times10^-13)=13-0.3010=12.699`


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