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If `0.765 g` of an acid gives `0.535 g` of `CO_(2)` and `0.138 g` of `H_(2)O`, then the ratio of the percentage of `C` to `H` isA. `19 :2`B. `18:11`C. `20:17`D. `1:7` |
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Answer» Correct Answer - A `%` of `C=(12)/(44)xx(0.535)/(0.765)xx100=18.07` `%` of `H=(1)/(18)xx(0.138)/(0.765)xx100=2.004` Ratio of `%` of `C , H = 19 :2` (approx) |
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